According to Einstein, in the photoelectric effect, the energy of the photon is converted into the kinetic energy of the electron.
Then according to Einstein himself (E=mc2), why is it not converted into mass? Then which energy is converted into mass?
Well, suppose the energy of the photon is converted into the kinetic energy of the electron, then who will decide in which direction the electron will go? If we consider the conservation of momentum, like in the Compton Effect, then it should go in the same direction as the photon, that is, the electron should enter the metal even more. But it comes out in the opposite direction of the photon, how is this?
Einstein says that an electron absorbs the energy of a photon completely or partially, can anyone tell us how it absorbs it? Is there any mechanism in the electron that allows it to absorb the energy of a photon? Well, what kind of energy is in the photon? What is its nature? If an electron absorbs a low-energy photon, what happens to that energy? Why doesn't the electron come out of the metal surface by absorbing two low-energy photons one after the other?
If Einstein says that an electron can absorb the partial energy of a photon, then why doesn't an electron in an atom absorb the partial energy of a photon of higher energy and go to the desired energy level? Then why does it take a photon of exactly that energy difference to go from one energy level to another?
Why don't we think about it? We have lost our tendency to think. This will cost us a lot.
We know perfectly well that the energy of any electromagnetic wave cannot be concentrated at one point. This is a universal truth.
Light waves are electromagnetic waves, so Einstein didn't consider how the fields in them could apply forces on electrons. Think about this and you'll get the answer.
Then why should we be so submissive to Einstein? We also have the intelligence to think. We just have to decide to think logically. Otherwise, the coming generation will make fools of us. It has begun. The truth cannot be hidden for long. For this, read 'Classical Explanation of Photoelectric Effect' published by IEEE Xplore in April 2025.
Thank you for your great analysis. I am still trying to understand some things but I am facing a lot of difficulties.
First let me mention that in the equation I mentioned E=mc2 where m=mo/sqrt(1-v2/c2), as you said, this is what is expected. This means that if the mass is in motion, then it's just like that m>m0.
Again, we understand that the fusion process, in stars, releases a vast amount of energy because the total mass of the resulting nucleus is less than the combined mass of the original nuclei, with the "missing" mass being converted into energy. This released energy is emitted as electromagnetic radiation, including visible light, infrared radiation, ultraviolet radiation, and other forms of light. So I understand that the energy of a photon is also the energy of an electromagnetic wave, so what's the problem with it being converted into mass? That's all I wanted to say.
The next question is that in the photoelectric effect, when an electron is emitted at a maximum speed, it absorbs the whole energy of a photon, meaning that photon no longer exists there. In such a case, the electron should get the full momentum of that photon, so there is no other option but for that electron to go in the same direction as the photon was going. But in the photoelectric effect, all the electrons are seen coming out in the opposite direction of the photons. That means someone is pulling them out and that someone must be the electric and magnetic fields in that light wave. There is a need to study this direction, which has not been done yet, that's all I wanted to say.
But in the paper, DOI: 10.1109/ICAECT63952.2025.10958964, such an attempt seems to have been made to a small extent. This is worth reading once.
I realize now that the title of this discussion is a bit inappropriate, but I'll be careful from now on.
I hope that some concrete conclusions will emerge from the further discussion.