Hello everyone.
Im seeking some help regarding the attached assignment. I can see from the DEPT 135 analysis that the compound must have 8 carbons: CH/CH3, C, CH/CH3, C, CH/CH3, CH/CH3, C and C.
And i can see from Mass spec. that we have an M+ Peak at 214 and M+2 peak at 216.
The peak at 1686 in IR could indicate an amide, nitril or an C=O from carboxylic acid, right?
I hope someone could help with the final compound structure and the "right" way to approach this assignment or if someone have any Tips/tricks?
All spectra were acquired on a 800 MHz NMR spectrometer dissolved in DMSO-d6.
thanks:)
In 1H NMR spectra there are un AB system with 3J coupling equal to 8.4Hz and one singlet at 7.55 ppm of the aromatic part; then the three substituents are in the 1, 2 and 5 positions. The two 1H that constitute the AB system are between Br and the CH3. The Br is in the position 2 and the CH3 in the position 5 the structure will be stabilized by a weak hydrogen bond Br...H-O. The others positions can't give the form of the aromatic part.
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