If a muon is just a massive electron that decays into an electron and associated neutrinos and anti-neutrinos, then where are the corresponding hadrons (protons/mesons) for these leptons? Considering Kaons have cosmic origins, are their decay hadron particles bound to the decay particles of muons?
first of all , a muon at rest has not enough energy to decay into muon neutrino + hadrons. Therefore the only channel open for it is muon->muon neutrino+ electron+ electron antineutrino.
On the other hand, tau (the heaviest variety of leptons) has enough energy to decay in nu-tau + hadrons (e.g. : tau->nu tau +pi0 + pi- )
Btw muon is NOT a heavy electron. Otherwise we would observe a mu->e + gamma transition (there is a new experiment at Fermilab named Mu2e searching for exactly this decay).
According to the Standard Model, there are no "corresponding hadrons" for the leptons. Each of the 3 particle generations consists of the lepton, its neutrino and two quarks having the electric charges of +2/3 and -1/3. And of course the antiparticles.
1st generation consists of: electron, e-neutrino, u and d quarks.
2nd generation consists of: muon, mu-neutrino, c and s quarks.
3rd generation consists of: tau lepton, tau-neutrino, t and b quarks.
Hadrons are complex particles (not really elementary) that are formed of quarks and gluons. For example, proton consists of uud quarks.
K+ = u + anti-s
K- = s + anti-u
K0 = (d + anti-s) or (s + anti-d)
The neutrino in the decay must be a muon neutrino not an electron one. This is kind of important in your speculation.
first of all , a muon at rest has not enough energy to decay into muon neutrino + hadrons. Therefore the only channel open for it is muon->muon neutrino+ electron+ electron antineutrino.
On the other hand, tau (the heaviest variety of leptons) has enough energy to decay in nu-tau + hadrons (e.g. : tau->nu tau +pi0 + pi- )
Btw muon is NOT a heavy electron. Otherwise we would observe a mu->e + gamma transition (there is a new experiment at Fermilab named Mu2e searching for exactly this decay).
You cannot say "corresponding Hadrons to the leptons" because leptons are elementary particles but not Hadrons. Hadrons are made up of Quarks and thus you can say "corresponding Quarks to the leptons". And its matching as we all know, there are 3 generations of Leptons as well as Quarks.
And a muon cannot decay to any hadron as its invariant mass is far less than that of Hadrons...
Your statement "kaons are of cosmic origin" is only partially correct. Kaons, in fact, were discovered when exposing cloud chambers to cosmic rays, but now they are copiously produced in accelerators, as many other unstable particles. By the way, charged kaons have many decay channels and two of them have a muon as one of the decay products (this is so called a weak decay that is mediated by a weak force).
You will perhaps find answer to this question in my work available online:
http://kvisit.com/S2uuZAQ.Igor.
You can consider following decay mode of Kaons
which is a purely leptonic channel.
K^minus --> pi_zero + mu^minus + nu_mu^bar
The Feynman diagram is attached below. Source is
http://www.futura-sciences.com/magazines/matiere/infos/actu/d/physique-nicola-cabibbo-naura-pas-prix-nobel-physique-il-vient-mourir-24822/
Now this mu^minus decays again, Feynman diagram is given below,
The final product is one muon anti neutrino one electron
anti neutrino, one muon neutrino and one electron.
This is a purely leptonic decay channel. This decay channel
has NO hadronic jets in the final state. Thus channel was
used to study the atmospheric neutrino anomaly. I hope this
helps.
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