a reaction requires me to take catalyst defined as a particular moles of Ru. But I am not sure if there is 1 carbon for every Ru (ruthenium) in that catalyst powder from Aldrich.
Usually Ru/C (ruthenium on carbon) is about 5 weight percent of Ru and 95% carbon, its possible you have the 10% version (10 weight % of Ru) as well. So you would need about 2,02 g of this material for 1 mmol of Ruthenium from the 5% and half of that of the 10% .