Jan Ivanouw To solve the equation log(m)=a+b⋅x follow these steps:
Given Equation:
log(m)=a+b⋅x
Step 1: Isolate x
log(m)−a=b⋅x
Step 2: Solve for x
Divide both sides by b(assuming b≠0:
x=[log(m)−a]/b
Final Solution:
x=1/b[log(m)]−a/b:
The base of the logarithm matters: If it is a common logarithm (log10), the equation is interpreted as above. If it is a natural logarithm (ln, base e, the same steps apply.
The equation is only valid if m>0as the logarithm is undefined for non-positive values of m and zero. Regards--Ijaz