How to explain the presence of a hydroxyl group in NMR analysis of lanthanide diamine salicyaldehyde complex which is used as a catalyst for deprotonation reaction? Can hydrogen bond in such complex be broken and how?
The presence of OH group in NMR is identify first by recording 1H-NMR then you add D2O and record again 1H-NMR that time OH peak will not appear due to exchange with solvent. ThT will clearly shows presence of OH group.
Usually NMR peak for hydrogen connected to electron negative atom like N, S or oxygen is broad and disappear when you add D2O to the sample.Your question about hydrogen bond : for inter -molecular hydrogen bond you can try very dilute solution or gas phase to eliminate hydrogen bonding . Good Luck
I agree with Salim's answer, if you lucky you could see the OH peak but most of the time is hard to show and due to the ion exchange it will disapear when you add D2O, try to do 2DNMR cosy