·         Go to Load menu and choose BC and create a boundary condition

·         Choose displacement/rotation, click on continue

·         Pick the point you wish to apply displacement, when finished, click on “done”  you will get the “edit the boundary  condition” menu. You can apply three displacements and three rotations. Suppose you want to apply  5 millimeter displacement in U3 to a node.

·         Tick U3 and enter 0.001m in the box. Look at the amplitude is at the bottom. Don’t choose instantaneous.  Click on the symbol and you get a little window

·         Choose tabular and make a table like this

0.0, 0.0

60, 1.0

120, 2.0

180, 3.0

240, 4.0

300, 5.0

What the above process does is to apply 5mm displacement in 5 minute. If you are not doing a dynamic analysis, this process doesn't make much difference. The only thing this does in a static analysis is to apply the displacement slowly. Time hasn't got much meaning in a static analysis.

First think why you want to apply the load slowly. What are you going to gain from it.

Hi Jiadong

Go to the load module, boundary condition, displacement/rotary.

then, put your value in desired direction (depends on your amplitude).

hope it helps you.

dont hesitate to ask if you are still confused. 

Best Lucks

Hi

Displacement boundary condition is another type of load.

In a linear or perturbation analysis, Abaqus  either ramps the load. In the process Abqus uses a pseudo time which varies between 0 and 1.

In you case you define a time history of the displacement. Note that Abaqus works in seconds not minutes.

You can do above either directly or multiply the maximum displacement with an amplitude definition as a tie function.

The rest is as Khaled said. 

Thank you, Khaled Ghaedi and Sirous Yasseri, I found something associated with the displacement load in ABAQUS and two screenshot are in the attached file. I still confuse about what should be inputted in ABAQUS if I want to impose a displacement load about 1 mm/min on my structure.

·         Go to Load menu and choose BC and create a boundary condition

·         Choose displacement/rotation, click on continue

·         Pick the point you wish to apply displacement, when finished, click on “done”  you will get the “edit the boundary  condition” menu. You can apply three displacements and three rotations. Suppose you want to apply  5 millimeter displacement in U3 to a node.

·         Tick U3 and enter 0.001m in the box. Look at the amplitude is at the bottom. Don’t choose instantaneous.  Click on the symbol and you get a little window

·         Choose tabular and make a table like this

0.0, 0.0

60, 1.0

120, 2.0

180, 3.0

240, 4.0

300, 5.0

What the above process does is to apply 5mm displacement in 5 minute. If you are not doing a dynamic analysis, this process doesn't make much difference. The only thing this does in a static analysis is to apply the displacement slowly. Time hasn't got much meaning in a static analysis.

First think why you want to apply the load slowly. What are you going to gain from it.

By defining displacement in BC, which results in "displacement control" type of loading

Thank you very much, Sirous Yasseri and Mehdi Lima. It's very kind of you to give me so detailed information, Sirous Yasseri.

Hello, Jiadong,

Instead of applying displacement boundary, you can apply velocity directly. If the time step is 1 second, you can apply 0.01666667 mm/second, which equals to 1mm/min

Thank you very much, Weiming Lan, I will try it.

Is your material properties loading rate dependent? If not, applying displacement is equivalent to applying velocity.

You can set your BC at desired direction with given value. If you want to do the monotonic/cyclic analysis, you can use amplitude to define the value for incremental displacement. Hope this help.

Regards

Thank you Weiming Lan and Asdam Tambusay, I have solved this problem. Thank you very much.

First go to Load, then Create Boundary Condition, Then displacement /rotation. Then you can check which direction you want and enter the displacement value.

can you share how you solved it

some of us are interested in learning from this