When RREQ packet is sent, one node encapsulates the packet such that other nodes on the way are prevented from increasing the number of hop counts. When this encapsulated packet is received by the other wormhole end, it is decapsulated to its original form and forwarded in its local area. Thus the destination or other nodes in local area of second colluding node considers the two colluding nodes as direct neighbours and the path through them as the shortest path

thank you so much Abhishek Tayal for your answer !

Yes , I understand what you saying , but right now i am not sure about the link or path between the 2 malicious node , i know it uses legitimate node path between let say M1 and M2 , so now is this link the same speed power as any path in the topology ? my second question is the destination node depend only on the shortest path ? or on the fastest path ?

The path is usually determined by the 'cost' metric. This is your choice, for ex: it could be number of hops, or it could be highest bandwidth, or least latency etc.

It depends on the routing protocol being used,

thanks Abhishek Tayal