Dears

I have a cluster of the general formula :

[(P4W6O34)2Co2Na2(H2O)2]18- and I found only (Na10(H2O)18)10+

The rest 8+ of charge may be attributed to undetermined sodium disorder cations or (H3O)+ . From single crystal X-ray, it is obvious that there is no more than water and my question is how to show that there is (H3O)+ or not and in case of si, how to determine there exact location and whether they are inside the cluster or free protonated waters inside the lattice. 

As shown in the formula, it contains cobalt which is a headache and  so it is difficult to be analyzed by H-NMR . In addition, the TGA shows two types of water with 27H2O which is agree with the crystal solution.

N.P.

Attached The 31P-NMR of the title compound.

This is a question from the refree: The charge of the polyanion (-18) as shown in the title and throughout the manuscript is wrong. If the six phosphate groups are indeed protonated, as claimed, it should be rather -12 (see also the final formula of the hydrated salt). At the same time, protonation of the oxygens of these groups is not supported by results of bond valence sum calculations shown in Table 3. Therefore the missing protons could easily be present within hydronium counterions. This issue should be further elaborated and discussed.

Sincerely, Yours

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