I have simulated the reconfigurable antenna using PIN diodes using HFSS software.Now for the hardware implementation i am not getting how to give current to the diode.
Should i use RLC circuit to give current to the diode?
In CST program, we use the lumped element tool to represent the PIN or varactor diode. from datasheet of the used PIN diode, you can use the equivalent circuit of it to determine the RLC circuit and the appropriate values of R, L, and C. in software program, you can only change these value to evaluate the performance of your design. but to make a practical test, you must manufacture the design and then supply it with the necessary voltage according to the datadsheet.
To bias/unbias the diode,
1) In case of low freq, HF, lower vhf you can use centre tap at transformer secondary side. DC current to be provided through centre tap point of transformer to diode. Suitable capacitor to use for RF bypass to protect psu against RF
2) In case of UHF and above, R, L, C circuit to bypass RF to psu and back to back diode, to avoid DC current to flow towards RF source.
Thankyou Amipara Manilal sir for your response.
I have designed the antenna for 2.45 GHz so i am using RF choke in series to diode and then a capacitor.
My question is I am exciting a parasitic plate using this diode, so is there is a need of any high impedance matching line of lambda/4 between the diode and the LC circuit? or can i give DC supply directly to RF choke then the current will pass through the diode and then to the parasitic plate.
I felt that matching line is not required as it is not a radiating antenna if i am wrong kindly correct me.
And Is resistor and RF choke both are required?If it is required then how to select the RLC values.
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