Air sampled filter papers were analysed for chemical compostion using AAS.
The results were in mg/kg.
How do i convert mg/kg to ug/m3?
mg -> ug: multiply by 1000 (1mg = 1000 ug)
kg -> m3: divide by density of the sample (X m3 = 1kg/density)
regards,
G
Dear Professor Grzegorz
I have air filter papers.
The initial weight of the filter paper is 142.046 mg and final weight after collection of pollutants it is 142.302 mg.
I analysed 142.302 mg weighed filter papers for element composition using AAS.
I got the results as
Al = 1354.992 mg/kg
Fe = 122.644 mg/kg
K = 1547.116 mg/kg
Na = 1125.175 mg/kg
Can you please suggest me the conversion method in finding out the Al weight for my samples.
If i inderstand you procedure
We substract the final weight from initial weight to get the sample weight:
142.302-142.046=0.256 g = 0.000256 kg
Then multiply the sample weight in kg with your con. in mg/kg to get the amount of element in mg
e.g.:
For Al: 0.000256×1354.992=0.3469 mg
Regarding the first Q.
Devided by density in kg/m3
Then muliply by 1000
(mg/kg) × (m3/kg) × (1000 mg/m) = ug/m3
Dear Khaled
But i digested the entire filter paper for the analysis. So i have to consider the entire filter paper weight with pollutant as my sample weight.
And in that whole weight, the composition of elements is determined.
In that case, my weight of pollutant used for analysis is 142.302 mg. Then how do i determine the observed element composition weight from the pollutant weight.
Use this formula to calculate metal concentration in ambient air sampled filter papers:
C = (Ms – Mb) x Vs x Fa/V x Ft
Where, C = concentration, µg metal/m3. Ms = metal concentration µg/mL Mb = blank concentration µg/mL Vs = total volume of extraction in mL Fa = total area of exposed filter in cm2 V = Volume of air sampled in m3 Ft = Area of filter taken for digestion in cm2
Dear Arideep
Thanks for the suggestions.
Will try using your idea.
I found your profile similar to my area of interest.
Are you interested in doing any collaborative research?
Arideep's formula is incorrect. You have take the ratio of the digested area to the total area of the filter, so in his terminology it would be Ft/Fa. (Ms-Mb)*Vs gives you the result of the analysis of the area of the filter sampled in terms of total ug. Ft/Fa gives you the calculated ug for the entire filter. Divide that by V (volume sampled in m3). You will end up in ug/m3.
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