Dear Dr. Gorji

You can find the answer here:

http://www-pub.iaea.org/MTCD/Publications/PDF/Pub1564webNew-74666420.pdf

or please search this question in researchgate:

"The formula for radiation dose of an x-ray unit D = g*kV*mAs/d^2 where g is constant and d=distance, in what kind of dose does it refer to?"

As Sajad recommended above, please have a look at recent questions on that topic.

For example:

https://www.researchgate.net/post/Can_we_calculate_radiation_doses_to_patients_undergoing_fluoroscopy_exams_using_the_kV_mA_and_Exposure_time_fluoro-time

and

https://www.researchgate.net/post/How_to_calculate_X_ray_dose_using_mAs_and_kV_without_using_any_detector

Additional remark:

@ Sajad; direct linear proportionality of x-ray dose to kV is not known to me. Sorry, but things are not so simple. Direct proportionalities to mA*s and 1/distance² are ok.

See for example the curve calculated by U. Neitzel in:

https://www.researchgate.net/post/How_do_I_calculate_the_Air_Kerma_value_Air-Kerma_or_Air-Kerma_Rate_from_an_x-ray_system_through_the_kVA_and_mAs_values

In the following link you will find an example of quite good quadratic dependence on kV (i.e. on kV²):

https://pdfs.semanticscholar.org/3aa6/34f5c3b3289f7e5dbdaf7a3ecabf7ee91e3b.pdf

Dear Dr. Martens

Thank you for your helpful answers. Yes that's correct. As you mentioned, this is not simple and the best simple answer is that Dose is depend on kV2.

This was title of a same question which were discussed by some other people and I have referred readers to that question.

Sorry Sajad,

there was a misinterpretation on my side.

I havn't read your answer above not carefully enough.