Similar to moon artificial satellites are also responsible for gravitational force which may be minute in quantity but might affect tides more than Earth
They don't effect the tides at all. It takes a large mass to produce a measurable gravitational field, and a much larger mass to produce tidal effects; and satellites are always as light as possible, to reduce the difficulty of getting them into space in the first place.
The previous answer said it all. You could have calculated the ratio of the moons mass to the ones of the satellites assuming maybe a total of 100000 metric tons or maybe even a factor 10 more. The mass of the moon is about 7.3E22 kg or 7.3E19 tons hence a power of 1E18 or 1E19 more.
You can easily calculate many natural influences by simple formulas, but they may be negligible in practical life. E.g., I can calculate the attraction force of black hole in M87 galaxy to my body.
Tides are caused by gravity, and gravity is a really weak force. The mass of the Moon is 7 x 1022 kg, and it causes tides where the difference between water levels is on the order of 10 m. Satellites are on the order of 103 kg, and they're 103 times closer, so the tidal effect caused by the average satellite is 1013 times smaller, and that's too small to be measurable. Another factor is the number of satellites: 1000 sats in orbits evenly distributed around Earth will cancel out each other's tidal effects.