Mukesh Yadav The conversion of ATP to energy in kilocalories involves a standard value of about 7.3 kilocalories per mole of ATP hydrolyzed.

Energy released (kcal)=Number of moles of ATP×7.3kcal/mol

Number of ATP molecules = 38

Standard energy release per mole of ATP = 7.3 kcal/mol

Total energy released = 38 ATP molecules * 7.3 kcal/mol = 277.4 kcal

Under optimal conditions, aerobic respiration can release approximately 277.4 kilocalories of energy, captured in the form of 38 ATP molecules, from the complete oxidation of one glucose molecule.

Hey there Mukesh Yadav! Well, you're diving into the energetics of cellular respiration, and it's a bit of a rabbit hole. The theoretical maximum energy yield from the complete oxidation of one glucose molecule during aerobic respiration is indeed 38 ATP molecules. However, translating that into kilocalories (Kcal) involves considering the energy stored in each ATP molecule.

On average, it's estimated that the hydrolysis of one mole of ATP releases about 7.3 Kcal of energy. So, if we multiply 38 ATP by 7.3 Kcal (as Alvena Shahid), we get an estimated yield of around 277.4 Kcal for the complete oxidation of one glucose molecule during aerobic respiration.

Keep in mind that these are theoretical values, and actual energy yields can vary due to factors like the efficiency of cellular processes and the specific conditions under which they occur. Different sources might provide slightly different numbers based on their assumptions and measurements. If you Mukesh Yadav have specific sources in mind, it could be interesting to delve into the details of their calculations to understand any variations.

Thank you Alvena Shahid & Kaushik Shandilya for your answer but I got confused after seeing the equation of oxidation of 1 molecule of glucose during aerobic respiration. Is there any explanation of this equation?