Did Anyone has the Experience to calculate the power generation from Syn-gas?
Please let me know how much power will be generated from 1 Nm3 Syngas at 1 barg pressure with heating value 800-900 Kcal/Nm3.
or How much volume of Syngas at 1 barg will be required to generate 1 KWh power?
Please provide reference if possible.
Regards.
Dear Muhammad,
that strongly depends on the power conversion technology you plan to use. Is it in a gas turbine, in a combined cycle, a gas engine, or a fuel cell? What size, what specific technology? Those factors influence your electric efficiency.
Generally, you can calculate electrical power production by multiplying electric efficiency with heating value. In your specific case, this means you will have to transfer heating value of syngas from Kcal to kWh (800 kcal is ca. 0.93 kWh) and multiply it with efficiency. If electric efficiency is e.g. 0.40, then 1 m³@800kcal/m³ would generate about 0.372 kWh. Reference should be any standard thermodynamics or power technology book.
Best regards,
Andreas
Dear Brother Andreas Ortwein ,
Thanks for your valuable answer. its solved my problem.
Prays & Regards.
Please take care the basic Mechanical Eq: PV=RT
Electrical Equation: Energy=Power*Time=VIT=ELECTROMOTIVE FORCE*CURRENT FLOW*TIME in kWh
One Unit (=1kWh) of energy cost around 4-5 Rs (Indian currency)
Dear Andreas Ortwein ,
I need the equation to calculate the KWh of Power production from Heating Values(KCal/NM3) of gas relation, with Syn Gas Power Generator efficiency.
As you Calculated above:
("you will have to transfer heating value of syngas from Kcal to kWh (800 kcal is ca. 0.93 kWh) and multiply it with efficiency. If electric efficiency is e.g. 0.40, then 1 m³@800kcal/m³ would generate about 0.372 kWh.")
that Simplified mathematical Relation from where your calculate the 0.372 KWh.
Thanks and Regards.
P_el = eta_el * P_fuel
P_el is electrical power, eta_el is electric efficiency and P_fuel is fuel power.
Fuel power for 1 m³ is 800 kcal which roughly equals 0.93 kWh.
Electric efficiency is 0.4 for the example (this can differ strongly depending on technology).
Dear Andreas Ortwein,
Thanks for your response but I also want to know how you calculated (Fuel power for 1 m³ is 800 kcal which roughly equals 0.93 kWh.)?
Please...
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