If natural fibre micron size increase, what about the thermal conductivity of polymer composite material. pls explain the mechanism behind that.
Finally it will depend upon the volume fractions of the fibre and the matrix only.
Volume fraction of fibre and matrix is nothing but the cross sectional areal fractions. Assume your composite specimen has a cross section of 20mm width and 10mm thickness. Cross sectional area is 200mm2. If the fibre occupies 120mm2 and the matrix 80mm2, then the fibre areal/volume fraction is 120/200=0.6 or 60%. Balance matrix/polymer is 40%.
Thermal Conductivity of Composite = VF of Fibre x Thermal Conductivity of Fibre + VF of Matrix x Thermal Conductivity of Matrix.
TC of Composite = 0.6 x TC of Fibre + 0.4 x TC of Matrix.
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