I have Plant extract in different Solvent, I would like to combined it with antibiotics in different concentration and then i would like to take antimicrobial activity of it how would i make those combination ?
1- First, a Beaker or a crucible should be brought, weighed (Assume that the weight is 100 g)
2- Transfer the extract to the Beaker
3- The solvent used in the extraction process shall be disposed of by evaporation of until the dry matter is obtained as far as possible
4- The beaker is weighed after full evaporation of the solvent (Assume that the weight is 110 gm)
5- The weight of the extract (the weight of the beaker with the extract - the weight of the empty beaker) = 110-100 = 10 g
6- The extract is dissolved in the appropriate solvent Ethyl alcohol is often used and an emulsifier may be added (the amount of the solvent is calculated to obtain the desired concentration(
To prepare different concentrations:
1- The extract is dissolved in the minimum amount of suitable solvent and then a quantitative transfer is done to a volumetric flask with a final size of 100 ml (the appropriate size for the quantity of the extract).
The concentration of the extract is calculated as follows
10gm/100ml = 10×106µg/100ml= 10×104 µg/ml
Different concentrations could be prepared from that stock solution
To prepare 1000 µg / ml with a final volume of 100 ml
V1×C1 (before dilution) = V2×C2 (after dilution)( the concentration which we would to prepare )
? ×10×104 = 1000×100
V1= 1000×100/10×104= 1 ml
Take 1 ml of stock solution (Conc 100000 μg/ ml) and supplement with appropriate solvent to 100 ml in volumetric flask.
To prepare 500 µg / ml with a final volume of 100 ml
? ×10×104 = 500×100
V1= 500×100/10×104= 0.5 ml
Take 0.5 ml of stock solution (Conc 100000 μg/ ml) and supplement with appropriate solvent to 100 ml in volumetric flask.
To prepare 250 µg / ml with a final volume of 100 ml
? ×10×104 = 250×100
V1= 250×100/10×104= 0.25 ml
Take 0.25 ml of stock solution (Conc 100000 μg/ ml) and supplement with appropriate solvent to 100 ml in volumetric flask.
To prepare 125 µg / ml with a final volume of 100 ml
? ×10×104 = 125×100
V1= 125×100/10×104= 0.125 ml
Take 0.125 ml of stock solution (Conc 100000 μg/ ml) and supplement with appropriate solvent to 100 ml in volumetric flask.
https://www.researchgate.net/post/How_can_I_prepare_a_stock_solution_from_a_plant_extract2
Hi Dr. Patel
The method is in my research
Pharmacological synergism of bee venom and melittin with antibiotics and plant secondary metabolites against multi-drug resistant microbial pathogens
Antimicrobial Activities of European Propolis Collected from Various Geographic Origins Alone and in Combination with Antibiotics
best regards
Issanm
Hi Dr. Patel
The method is in my research
Pharmacological synergism of bee venom and melittin with antibiotics and plant secondary metabolites against multi-drug resistant microbial pathogens
Antimicrobial Activities of European Propolis Collected from Various Geographic Origins Alone and in Combination with Antibiotics
best regards
Issam
1- First, a Beaker or a crucible should be brought, weighed (Assume that the weight is 100 g)
2- Transfer the extract to the Beaker
3- The solvent used in the extraction process shall be disposed of by evaporation of until the dry matter is obtained as far as possible
4- The beaker is weighed after full evaporation of the solvent (Assume that the weight is 110 gm)
5- The weight of the extract (the weight of the beaker with the extract - the weight of the empty beaker) = 110-100 = 10 g
6- The extract is dissolved in the appropriate solvent Ethyl alcohol is often used and an emulsifier may be added (the amount of the solvent is calculated to obtain the desired concentration(
To prepare different concentrations:
1- The extract is dissolved in the minimum amount of suitable solvent and then a quantitative transfer is done to a volumetric flask with a final size of 100 ml (the appropriate size for the quantity of the extract).
The concentration of the extract is calculated as follows
10gm/100ml = 10×106µg/100ml= 10×104 µg/ml
Different concentrations could be prepared from that stock solution
To prepare 1000 µg / ml with a final volume of 100 ml
V1×C1 (before dilution) = V2×C2 (after dilution)( the concentration which we would to prepare )
? ×10×104 = 1000×100
V1= 1000×100/10×104= 1 ml
Take 1 ml of stock solution (Conc 100000 μg/ ml) and supplement with appropriate solvent to 100 ml in volumetric flask.
To prepare 500 µg / ml with a final volume of 100 ml
? ×10×104 = 500×100
V1= 500×100/10×104= 0.5 ml
Take 0.5 ml of stock solution (Conc 100000 μg/ ml) and supplement with appropriate solvent to 100 ml in volumetric flask.
To prepare 250 µg / ml with a final volume of 100 ml
? ×10×104 = 250×100
V1= 250×100/10×104= 0.25 ml
Take 0.25 ml of stock solution (Conc 100000 μg/ ml) and supplement with appropriate solvent to 100 ml in volumetric flask.
To prepare 125 µg / ml with a final volume of 100 ml
? ×10×104 = 125×100
V1= 125×100/10×104= 0.125 ml
Take 0.125 ml of stock solution (Conc 100000 μg/ ml) and supplement with appropriate solvent to 100 ml in volumetric flask.
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