In my opinion, when x=0, it means CoFe2O4. When x=0.1, it means CoZn0.9FeO4. Anyway, this constituent maybe is determined by xps.

Dear  Willey John,

Thanks a lot. But in the CoZn0.9FeO4 ,please explain about mole percent of Zn Doping percent ( namely 0.9).

Regards,

Abbas Rahdar

Molar ratio can be found by this way:

Co/Zn = x / 1- x

For any x value, you should compute Co/Zn molar fraction.

Dear  Satish Bolloju    ,

Thanks.i want to synthesis Zn1−xCuxS nanoparticles that Cu is doping agent with dopant content ranging from x=0.00,0.05, 0.10 .

I  prepare 0.1 M CuCl2 50 ml  ,So for x=0.00 ,1.oo ,2.00 , how much CuCl2  need in ml,respectively?

please answer for 0.1 M CuCl2 50 ml  and x=0.00 ,1.oo ,2.00 , how much CuCl2  need in ml,respectively.

Dear  Fernando Acosta-Humánez,

Co/Zn = x / 1- x or Zn/Co = x / 1- x ?

Dear Fernando Acosta-Humánez,

for Zn1−xCuxS nanoparticles  , you said Cu/Zn = x / 1-x  (Cu is doping agent )and for Co(1-x)ZnxFe2O4  nanoparticles you said Co/Zn = x / 1- x (Zn is doping agent ) . please explain this difference?

Dear Mr. Abbas Rahdar,

Did you get your problem solved, please?

I am here to help you. Please let me know if you still need this help. I am looking forward to hearing from you.

Dear Sir, still it is not clear that how to calculate atomic percent doping and mole percent doping