I know this equation.

 D=Kλ/(β cos θ) , β = FWHM*2π/360

i got this from one of my experiments

by data, k= 0.9, λ=0.154nm, θ=7.21, β = FWHM*2π/360=0.1635*2π/360

If these data are right, the answer is 14.58nm right?

i really want to check this diameter.

please let me know 

or could you give me other material so that i can understand please...

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