I know this equation.
D=Kλ/(β cos θ) , β = FWHM*2π/360
i got this from one of my experiments
by data, k= 0.9, λ=0.154nm, θ=7.21, β = FWHM*2π/360=0.1635*2π/360
If these data are right, the answer is 14.58nm right?
i really want to check this diameter.
please let me know
or could you give me other material so that i can understand please...