This question was inspired by the answers and discussions around a previous question,

What does Loschmidt's paradox tell us about the second law of thermodynamics? (https://www.researchgate.net/post/What_does_Loschmidts_paradox_tell_us_about_the_second_law_of_thermodynamics/3)

Assume for simplicity a monoatomic gas closed in a container. The container walls are assumed completely reflecting and totally opaque to heat. Assume that all the atoms are identical and spherically symmetrical.

Then the total state of the gas should be either symmetrical in all the particles (boson gas), or anti-symmetrical (fermion gas). In short, the particles are entangled, not independent. So, we can't represent the state of the gas as a product of the states of the individual particles.

A first problem is how do we define the entropy of this gas?

The simplest expression for the entropy is,

S = -kB Σj pj ln pj

where kB is the Boltzmann constant, pj is the probability that the system is in the j-th microstate, and the summation is carried over all the possible (orthonormal) microstates ψj of the system. So, if the gas is in the beginning of its evolution in some mixture of states, pj is the probability of the state ψj in this mixture.

However, as the container is completely isolating, the gas is a completely isolated system and it evolves unitarily. The number of states remains the same all the time. So how can the entropy increase?

Also, sometimes in discussing the paradox, people speak of reversing the evolution of the system by reversing the velocities of all the particles. But the particles are indistinguishable, s.t. under the quantum regime they loose individuality. Moreover, the indetermination in the particles' positions is as big as the dimensions of all the container. So, where is the particle whose velocity we want to reverse?

So, bottom line, how we formulate the paradox in the quantum regime?

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