Hi,
I came across the attached journal wherein quantum efficiency of luminescent material has been calculated from their PL and Reflectance spectra as follows:
The quantum efficiency of CeO2: x% Sm3+ phosphors were also evaluated by the following equation [41]:(4)ηQE=∫λP(λ)dλ∫λ[E(λ)−R(λ)]dλwhere P(λ), E(λ) and R(λ) are the normalized intensities for the emission, excitation and reflection spectra of the CeO2:xSm3+ phosphor, respectively. The quantum efficiency of CeO2: x% Sm3+ phosphors were also evaluated by the following equation: η (λ) = Integration of [λ P (λ) dλ] /[λ ((E (λ)-R (λ) )dλ], where P(λ), E(λ) and R(λ) are the normalized intensities for the emission, excitation and reflection spectra of the CeO2:xSm3+ phosphor, respectively.
Can anyone tell me exactly how to calculate the same?
Thank you.
As stated in the article, you need to have all three spectra. Then normalize them, i.e. integrate each and equal that to 1. Then apply the new values for P, E and R into the integrals in the equation for QE. Hope this helps.
collect UV and PL spectra of the fluorescent material, make calibration plot of both.
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