Q1. How can I prepare such a table which is attached below?
Q2: Which analysis should I do for this?
I will try to #Descriptive statistics but not found such table. I also do one way Anova.
Give your suggestions please
Thank you very much and wishes you best of luck Dr Agriculturist M. Hassain
In case of Chi Square: 16 cells (53.3%) have expected count less than 5. The minimum expected count is 1.58. So, it is not possible Dr Rabin Thapa. Thank you very much for your nice comments and suggestions Dr Rabin Thapa
Yes, i can do such analysis but there is not find such table. I will try again Dr Terri Purvis
. Thank you very much for your nice comments and suggestions DrTerri Purvis
I do not understand why you are reporting p values. These are descriptive statistics, not inferential tests of whether an independent variable is related to a dependent variable.
Thank you very much for your nice comments and suggestions Dr Rabin Thapa
I am not use this table. Thank you very much for your nice comments and suggestions Dr David L Morgan
Thank you very much for your nice comments and suggestions Dr Faraed Salman
Thank you very much for your nice comments and suggestions Dr Aparna Sathya Murthy
Which analysis should do for this? Dr Yehya A. Salih Waitting for your suggestion and thank you Dr Yehya A. Salih
From (insert) table. Use properties.
Use standard Error via Excel or genstat.
Which analysis do for this? Dr Ali F Almehemdi. Need your suggestion about this table and thank you so much Dr Ali F Almehemdi
When you compare the Mean ± SD for two groups, you use the T-test, but here you have more than two groups, so you can use one-way ANOVA to compare among Mean ± SD for more than two groups. For more information you can check the following link: https://brownmath.com/stat/anova1.htm#Terminology
I'm sorry, now I noticed the table clearly after I zoom in... There is a comparison between two groups, the first comparison is between Mean ± SD by T-test and the second comparison between the proportions is in a chi-square... You can use the Med-calculator even it needs to compare every two values ( it takes time but simple to use and accurate)...Or you can use SPSS.
I fully support the opinion of my colleague Manal Hadi Kanaan. Thank you!
Thank you very much for your nice suggestion and comments Dr Manal Hadi Kanaan but how can i do it? What the real/actual name of Med-calculator? I am waiting for your suggestions Dr Manal Hadi Kanaan
Thank you so much and wishes you best of luck Dr Raed Rahim Khuder
Thank you so much and wishes you best of luck Dr Lamia Mustafa Al-Naama
Thank you so much and wishes you best of luck Dr Кhrystova Tеtіana Кhristovaya T.E. Христова
I useful answer has been provided by Dr Manal Hadi Kanaan, all the best dear Ahasan Ullah Khan
Thank you so much and wishes you best of luck Dr Al-Baraa ABDULRAHMAN Al-Mekhlafi
If you want to compare between 3 groups with parameteric data then you can use ANOVA test.
If the data are non parmetric the compression between the three groups can be done by KrusKal_Walis test.
But for your table none of the above applies as the column 1 is the sum of the column 2 and 3.
Actually you have to analyse the between column 2 and 3. For which you can use chi-square test. Or since the values are given in percentage, you can also do z test of proportion.
Dear Ahasan Ullah Khan ,
For each variable, make a table with variable an country and compute a Chi-square test to test if the distribution in the three countries differs.
In Stata,
tabulate variable country, col nof chi2
I hope it helps,
José-Ignacio
Thank you so much for your suggestions and wishes you best of luck Dr Chowdhury/Chaudhury Meshkat Ahmed
Thank you so much and wishes you best of luck Dr José-Ignacio Antón
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