Hi
I am looking for the protocol to prepare different mol% of MBAA solution. I searched several articles for the protocol but couldn't find out the reliable one to follow. Actually I am confused about the calculation of mol percentage so I would be really grateful if someone please kindly help me to figure it out. Please note that I am going to use MBAA as a crosslinker for making polymeric hydrogel.
Thanks in advance.
Calculate molecular weight of each compound. Divide the taken mass by molecular weight. You got the amount in mole of each. Suppose your polymerization mixture contains monomer (s), initiator, and crosslinker. Now you need to calculate the mole % of crosslinker. Therefore, now divide the no. of mole by the total no. of mole in the mixture and finally multiply by 100.
To prepare 1 mol % of MBAA, you have to find out the moles of MBAA n(MBAA) and as well as for solvent n(H2O).
n(MBAA) = mass of MBAA /molecular weight of MBAA .
simlarly for H20. Then put down the values in below equation:
X(MBAA) = n(MBAA) / [n(MBAA) + n(H2O)]
now, calculate mol % of MBAA = X(MBAA) multiply by 100
Regards Tariq Mir
Md. Abdur Rahman and Tariq Mir
Thank you very much sir for your detailed reply. It will really help me to solve this problem.
Regards
Mohosin Rana
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