actually I need scientific way to increase alcohol content 9.4 v/v of volume 500 H to 9.6 v/v by using 9.9 v/v liquid?.
Alessandro Venditti
The solution proposed by Dr Ullah cannot be used since water and alcohol form an azeotrope and both evaporate in preconcentration.
Since you have two solutions in %v/v you may mix 3 volumes of the less concentrated solution and 2 volumes of the more concentrated one to obtain 5 volumes at the required concentration. I.e. 3 ml 9.4% + 2ml 9.9% = 5 ml 9.6%.
If you need a different volume of the final solution some simple calculations are necessary.
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