How can I convert the XRD pattern taken using Cu -K alpha to Fe?
Please have a look at the Bragg law:
lambda=2*d*sin(theta)
This equation has to be valid for both wave lengths (Cu and Fe -K-alpha).
So you have:
lambdaCu = 2*d*sin(thetaCu) and lambdaFe = 2*d*sin(thetaFe)
Taking the ratio you will have:
lambdaCu/lambdaFe = sin(thetaCu)/sin(thetaFe)
Solving for thetaFe you have to go via:
sin(thetaFe) = sin(thetaCu)*lambdaFe/lambdaCu
That's it.....
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