Dear Colleagues,
I considerd a metal cavity in air host medium. I want to obtain the Purcell Factor forom followin equation:
F_P=(3/4Pi^2).(lambda/n)^3.Q/Veff
What is lambda: is it the wavelength of light in free space?
what is n? is it n is refractive index of air n=1?
Did I understand correctly?
Gerhard Martens
Dear Ferydon Babaei-Taleshi
,yes, you did understand correctly...
lambda is the vacuum wavelength*) and n is the refractive index of the medium inside the cavity.
See for example:
https://en.wikipedia.org/wiki/Purcell_effect
*) you call it 'wavelength of light in free space'
Best regards
G.M.
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