how can I convert fertiliser amount from mg/pot if I have pot volume 10 kg soil or diameter of pot
This topic has been expounded previously. Briefly there are two methods based respectively on the: 1) the surface area of the pot; and 2) mass of the soil in the pot and field bulk density
This topic has been expounded previously. Briefly there are two methods based respectively on the: 1) the surface area of the pot; and 2) mass of the soil in the pot and field bulk density
Volume to Weight conversion based on density.
Calculation Formulas:
- weight w = ρ × v
- volume v = w ⁄ ρ
As a general role you can read the pending file of converting from
g/pot to kg/ha ,and you can alter the process:
Thanks all of you guys for your valuable answers, I really appreciate that.
I am OK with Paul's answer ; sol weight per ha depends on ploughing depth ; we normally meet in litterature between 3000 to 5000t/ha.
Thanks a lot for answring my question , I know all methodes that you have mentioned but I am doing something diffrent I wanted to use fertiliser rate in kg/ha form privious studies but some of these studies did not give enough information about pots or mass of soil. I need this for meta-analysis.
Thanks
Generally we take 30cm soil depth in calculating dose in Kg/ha. The soil volume will be 0.3×10000 and convert into by multiplying BD. From this we can calculate fertilizer dose in 1 ha soil weight. Similarly can be calculated in given weight of pot soil.
IT IS VERY SIMPLE, JUST MULTIPLY THE VALUE of mg/pot/kg to 2.23 it will be converted to kg/ha. 2.23 is a conversion factor for this.
The pot size is very important in your conversion. Is it 5, 10, 15 or 20 kg.
10, 000 square meter i.e. 1 Ha plough layer soil weighs about 2,240,000 kg. contaiN think this hint should be helpful.
The conversion can only be done, if you have the bulk density of the soil and the depth of sampled soil. The conversion then is just
mg/g * bulk density [g/cm³] * sampling depth [cm] * 100,000,000 (conversion factor from cm² to ha) / 1,000,000 (conversion factor from mg to kg) = kg/ha
The conversion can only be done, if you have the bulk density of the soil and the depth of sampled soil. The conversion then is just
mg/g * bulk density [g/cm³] * sampling depth [cm] * 100,000,000 (conversion factor from cm² to ha) / 1,000,000 (conversion factor from mg to kg) = kg/ha Generally we take 30cm soil depth in calculating dose in Kg/ha. The soil volume will be 0.3×10000 and convert into by multiplying BD. From this we can calculate fertilizer dose in 1 ha soil weight. Similarly can be calculated in given weight of pot soil.
The pot size is very important in your conversion. Is it 5, 10, 15 or 20 kg.
10, 000 square meter i.e. 1 Ha plough layer soil weighs about 2,240,000 kg. contaiN think this hint should be helpful. i am with John sirs answer...........
The conversion can only be done, if you have the bulk density of the soil and the depth of sampled soil. The conversion then is just
mg/g * bulk density [g/cm³] * sampling depth [cm] * 100,000,000 (conversion factor from cm² to ha) / 1,000,000 (conversion factor from mg to kg) = kg/ha
This is the amount you took for soil in your pot... so you can easily convert it by multiplying the value by mg × 2 million kg devised by soil per pot.
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