Why do the element stiffness of a beam decreases due to an application of an axial compressive load even if it's not related (directly) to any external effects?
Physically, one can understand that the element stiffness of a beam decreases in axial compression load and increases in an axial traction load.
Essentially, it is due to the second order term of strain and in compression result in diminishing the total stiffness Ktotal when increasing the geometric stiffness by P*Kg, as Ktotal=(K+P*Kg).Critical loads Pcr are P such that det (K+P*Kg)=0 (where P0).
So, for certain loads it is possible to have geometric stiffness Kg cancelling the classical stiffness K (and it can also be mixed with inertia effects,etc).
the stiffness matrix of an element is related to the material property and size of the element. if the stress of the element is below the yield stress, the stiffness is constant and doesn't change with increasing the applied load (because the young modulus is constant). but if yielding happens in an specific element, it's stiffness matrix will change in each time increment. this is due to change of the D matrix in plastic region.
It meant by the element stiffness is flexural or bending stiffness of a beam. This stiffness is mathematically reduced when applying an axial external comressive load as its produced a secondary negative action on it.
Physically, one can understand that the element stiffness of a beam decreases in axial compression load and increases in an axial traction load.
Essentially, it is due to the second order term of strain and in compression result in diminishing the total stiffness Ktotal when increasing the geometric stiffness by P*Kg, as Ktotal=(K+P*Kg).Critical loads Pcr are P such that det (K+P*Kg)=0 (where P0).
So, for certain loads it is possible to have geometric stiffness Kg cancelling the classical stiffness K (and it can also be mixed with inertia effects,etc).