I would like to produce both SnO, and SnO2 powders, and have a process here and resources online are conflicting about whether the end product of the reaction below is SnO or SnO2. Please help!
Overall Reaction (not sure if this is correct but):
SnCl2.2H2O + 2NaOH =SnO.H2O + 2H2O + 2NaCl
The Sn(OH)2 is the precipitate upon reaction with NaoH, which is then heated to form SnO2 (apparently).
Synthesis steps:
Mix 1 mole of SnCl2.2H2O with 2 moles of NaOH in deionized water, stir well and heat for 20 minutes using a microwave at 300W. Resulting precipitate is centrifuged, washed multiple times with water and ethanol, placed in an oven at 80C for 24 hours.
Then the powder is annealed/heat treated at 400C for 2 hours.
Question:
I am not sure at what stage the SnO is formed, or even if SnO2 is actually formed from a tin(ii)salt, is that even possible? Apparently the salt color of SnO is dark grey, and SnO2 is off white, however I also read sometimes SnO can also be off white.......... has anyone done this before? And how do I get SnO and/or SnO2 from SnCl2.2H2O?
Refs:
A reference for SnO formation from Sn(ii) salt:
1) http://en.wikipedia.org/wiki/Tin(II)_oxide - indicating mixing the Sn(ii) salt in NaOH can yield SnO
2) https://www.cs.mcgill.ca/~rwest/wikispeedia/wpcd/wp/t/Tin%2528II%2529_chloride.htm website indicating that SnCl2 is not stable in air and can oxidize to Sncl4, which can then turn into SnO2 based on the above steps (is that what is happening)?
3) Chatgpt prompt said I can create SnO from Sn(ii) salt literally by doing the above (that is taking it, adding NaOH, filtering off the precipitate which is SnO)
Some references for SnO2 formation from Sn(ii) salt:
1) a response to a similar question: https://www.researchgate.net/post/What_amount_of_SnC22H2O_precursor_will_be_added_to_synthesised_tin_oxide_MWCNTs_using_hydrothermal_method
2) Article Microwave-assisted synthesis of SnO2 nanorods for oxygen gas...
(uses Sn(ii) salt to produce SnO2 with the process described above).