Suppose I have a 100 Farad, 2.7 V supercapacitor which has a dimension of length = 45 mm and Diameter = 22 mm. I want to understand-how these length and diameter values were fixed and if any design equation is guiding it?
The capacity of a supercapacitor can be measured in (F / g) or (F / cm2) or (F / cm3)
The working potential = 2.7, indicates the maximum potential to which the SC can be charged.
Using the equation:
Cs = I. t / m (Vf-Vi)
Cs = I. t / A (Vf-Vi)
Cs = I t / V (Vf-Vi)
Where i = is the discharge current
Where Vf-Vi = is the work potential
Where m = is the mass of the active material
Where A = is your area
Where V = is the volume, this can be found with the data: 45 mm and diameter = 22 mm.
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