In case of cyclic voltammetry one plots I vs. U obtained when voltage is changed as U=kt. We know that I=dQ/dt, and combining these two equations we get I=k*dQ/dU.

The charge-discharge curve is usually plotted as U vs. Q, but if you exchange the axes and differentiate the obtained plot, you will again get dQ/dU vs. U.

However, it is necessary to take into account that the charging conditions are different: in the first case the voltage increases linearly with time and in the second case this happens with charge. So two obtained dQ/dU vs. U curves will not be exactly the same: some parts will be stretched and some parts will be shrinked. But the peaks should be more or less the same and have more or less the same positions.

Thank you very much!