the pair has a same material, basically a steel. The maximum force exerted is 80 KN. The design limits the lubrication, so I am using material with high hardness to avoid wear. Higher the hardness of the material, higher the cost. I dont want to spend on the material which is over hard.
I assume hardness above 1.5 times of softer material is sufficient in case of dry sliding wear condition. But, as you are also providing lubrication so may be lesser value will also work.
The wear equation for two solids in contact is : V = K* I* W / H.
Where: V is wear volume[m3], K is Archard proportionality constant, I is Sliding distance [m], W is normal load [N] & H = Vickers Hardness of Softer Surface[Pa]. Ref : Page 493, Engineering Tribology, Stachowiak and Batchelor, Elsevier publications
Even if you are compromise on the hardness, there is bound to be wear on the softer material. If you equalize the hardness of the mating components then there is a chance of early failure of the components because of seizure failure. I feel that wear cannot be avoided. You can extend the life of the components by judicious selsction of hardness, surface finish and modifying the nature of contact.
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