according to your picture that firstly

the load multiple 5 for 1 steps

then load multiple 1 for 105 step

means that 50+105=155 * load

Ezzeldin Kamel Mohamed Thank you for your answer, So you mean the step will equal to 350kN /155?

No, If you are applying 350 KN,

The applied force will be 155*350 KN

If you would like to divide 350 KN pers steps, use lower step value which is wriirin out the brackets, and the step number is within brakets

Factor (number of steps)

Could it be like that:

0.1 (10)

That mean total load will be 0.1×10×350

if the applied load is 350

the steps means the multiple factor 0.1(10) = 1

and the load will be as applied

Expected load failure F = 350 kN

Enter load as a unit, 1 kN

Load factor (LF)

Steps (S)

Example 1:

Load steps: LF (s) : 5(70)

5*70*1 kN= 350 kN

at load steps (10), F= 5*10*1 kN= 50 kN

Example 2:

Load steps: 5(40) 3(50)

F= (50*4+3*50) 1 kN = 350 kN

Example 3:

Load steps: 2(25) 4(50) 3(50)

F = (2*25+4*50+2*50) * 1 kN = 350 kN

at load steps (5)

F = 2*5* 1 kN = 10 kN

Good luck