I think you can concatenate the short strings and build a longer string.

In the frequency mono bit test, It is recommended that the test sequence contains a minimum of 100 bits (i.e., n ≥ 100).

Let sum1 be the number of 1's and sum0 as the number of 0's. The P_Value is calculated as follows: 

Sn = abs(sum1-sum0);

Sobs = Sn/(sqrt(n))

P_value = erfc(Sobs/sqrt(2))

if P_value

Thank you so much for your answer but I'm talking about the attached paper in this question. :)

As explained by the authors on Page 311, the process is straightforward. In this case,

...

P_value = gammainc(9/2, chi2_obs/2); %is this what you are looking for?

...

I highly recommend you to carefully study the mentioned tests in (http://csrc.nist.gov/publications/nistpubs/800-22-rev1a/SP800-22rev1a.pdf) first.

Also the following link may be beneficial to you:

http://math.stackexchange.com/questions/75005/how-do-we-check-randomness

Hi

Let the keystream 1011010101 be tested by Frequency test and Runs test. The result of Frequency test is SUCCESS because the numbers of occurences of bits- zero and one in the keystream are equal. The result of Runs test is FAILURE because the adjacent bits of the keystream are dependent.

Frequency test examines the numbers of occurences of the bits in the keystream.

Keystream : 1011010101 Frequency Test SUCCESS p_value = 0.527089

Runs test examines the independence of the keystream bits. Runs Test FAILURE p_value = 0.005658.

The calculation of this sequence is assumed by Sn = X1 + X2 + ... + Xn. 4.41 If ε= 1011010101,then n=10 and Sn =1+ (-1)+1+1+(-1)+1+(-1)+1+(-1)+1=2. The test statistic for the observed sum sobs is assumed by sobs = . 4.42

sobs=.632455532 .

erfc(z) is 0.527089.

Thank you

Kaung