I want to prepare acrylic monomers from alcohols by reacting with methacrylol chloride. Can anyone provide me the reaction conditions or suggest me any literature where I can find that? Thanks in advance
Traditional conditions for reaction of an acid chloride with an alcohol to make the ester call for use of a chlorinated solvent (chloroform or methylene chloride) and small molar excess of a tertiary amine base (pyridine or triethyl amine) at low temperature (near zero degrees centigrade). One can also use excess alcohol as the solvent, with slow addition of the acid chloride (neat or in an inert solvent). "Greener" (more environmentally sound) conditions could include use of a solid base to scavenge the HCl generated by the reaction (sodium bicarbonate, potassium carbonate or a basic ion exchange resin, etc.) and nonchlorinated solvent. Work-up would include filtering off the HCl/base byproduct and washing the organic phase with water and saturated aqueous sodium bicarbonate solution to remove residual HCl, acid chloride as the acid sodium salt, and unreacted alcohol, followed by removal of any solvent (by distillation). For best purity, the product ester should be distilled under as high a vacuum/lowest temperature conditions you can achieve if the product is amenable (low enough molecular weight). The reaction should include a few hundred ppm of a hindered phenol radical scavenger like BHT (with air bubbled into the mixture) to protect your system from accidental polymerization. A quick literature search should locate your specific case unless you are using novel alcohol.
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