I would like to heat a die of 40mm outer dia and 20mm inner dia and the height of the die being 100mm. I would want to heat the the die to temperature gradient of 150degree celsius.
material being Steel
I have a standard induction coil with following specifications
Dia of coil wire 5mm
Dia of coil 50mm
number of winding 7
pitch 13mm
Power specs of the coil is 500 and it would take almost 120 second to heat my die element.
Now i would like to alter the dimensions of the Coil winding
Dia of coil being 65 mm
pitch 25mm
and number of winding 4
will it take same time to heat up the material which is 120 s?
if not can you please provide me the calculation ?
I would also need to know will the heating be possible even in the central axis of the die cylinder or it is restricted to certain length from the induction coil.
I have read that it has some penetration depth.? Can you please give me the calculation with the answer for the same.?
Just some rough assessment:
Lower inductance and resistance result in your new coil having a significantly higher power rating. A first guess: 1 kW - maybe more.
The time to heat your die depends primarily on the power rating of the coil, thus it will be reduced.
Your questi9n about the heated area is a bit difficult to answer - not knowing the geometric setup: heating is achieved via eddy currents in the die (caused by the alternatinh magnetic field), thus the area heated is the on where some magnetic flow exists. Similarily, the "penetration depth" depends on the magnetic properties of the die.
Thank you sir for you answer.
Can you suggest me the formula for power rating of the coil?
Because I have gone through many reference. But its quite different formula and the unknown are difficult to find out.
It would be more helpful for me if you could send me some link or book to find the calculation part for this question.
Hello,
the formula for the inductance can be found in some textbook or - certainly - in the web.
The problem: the properties of the core (µr - which is not necessarily a constant for a "real-world" core) go into the calculation. Eventually it might be easier to build the coil and measure the inductance of the old and the new coil - at 50 Hz. Or measure the current flowing - maybe using some reduced 50 Hz voltage (using a transformer) first.
Regards
Thank You sir,
But Basically I am not an electrical engineer. I have to use this electrical equipment for heating my Die.
What is the relation between the inductance and the heating energy generated.?
If you're not an E/E, it might be wise to seek help from somebody at least basically familiar with "electricity". "Playing" with grid voltage has some risks.
Re your question: for a given frequency the inductance - plus the resistance - result in an "effective resistance" that is the limiting factor. Then P = U2/Reff.
In reality things are a bit more complicated as the unductive heater acts like some transformer - adding the die's properties to the effective resistance. Thus I now refine my measurement suggestions from above: put the die in place when measuring resistance/inductance or the current for a given voltage.
Hope this helps. Maybe we'll continue when you have performed measurements.
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