Higher limit of C.I - lower limit of C.I / 3.92 is the formula I used, my question is that this gives me a standard error of the regular odds ratio as opposed as the Log odds ratio, so should I just calculate the natural log of the standard errors I get through the above formula or should I first convert the limits of the confidence intervals into their natural log and calculate the S.E then?
For your formula, higher limit and lower limit of Ci should be taken natural log first
e.g. CI of OR (2, 5), after taking natural log, it is (0.693, 1.609),
SE=(1.609-0.693)/3.92=0.2337
remark: 3.92 is 1.96*2
For your formula, higher limit and lower limit of Ci should be taken natural log first
e.g. CI of OR (2, 5), after taking natural log, it is (0.693, 1.609),
SE=(1.609-0.693)/3.92=0.2337
remark: 3.92 is 1.96*2
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