The powder mass flow rate mp is such as mp × 0.9428 = 48.2 kg solids h–1, based on the hypothesis of constant solids flow rate. So: mp = 51.1 kg h–1. The evaporation rate is 121.8 – 51.1 = 70.7 kg water h–1. Evaporation rate in the tower: 99% of the total, i.e.: 0.99 × 70.7 = 70.0 kg water h–1. Furthermore, we assume that the initial temperature of the material is room temperature, i.e., 20°C. The formula for calculating the amount of energy required to evaporate water is based on the specific heat capacity of water: It takes 4.19 kilojoules (kJ) of energy to heat one kilogram of water by one degree Celsius. Typical energy consumption: 25 to 50 kW per ton evaporated water. η p = W o - W i W s - W i where Ws is the absolute humidity of saturation along the same line process that joins Wo and Wi. Overall drying efficiency is a measure of how effectively the input energy into the dryer is used when drying the product.So if you start from room temperature of 21C, and make it to 100C, the boiling point of water (at sea level) then the temperature change is 79C. The energy needed E=SH times change in temperature times the total mass in grams (Which is 1000gram for a liter of water). The latent heat of vaporization for water is 225 kJ/kg-1: After reading the problem, identify the values for the latent heat of vaporization and the mass of the object m-2: Substitute these values into the equation: Q = L V × m. 3: Use the above equation to calculate the energy needed to change phase. Now, heat from steam = heat required by the solution, Therefore quantity of steam required per hour = (4.57 x 108)/ (2.34 x 106) = 195kgh-1Quantity of steam/kg of water evaporated = 195/167 = 1.17 kg steam/kg water.