In supercapacitor we find specific capacitance from CV curves but I am confuse about one digit error I attach a file in which specific capacitance is calculated by authers by using this formula
Specific capacitance = Area of Cv curve / potential window * Mass of active electrode * scan rate
Example
Area of Cv = 0.01022
Mass of electrode = 0.04
Scan rate = 0.01
Potential window = 0.8
When I added all values in above formula then ans is 31.937
But Authers give ans 319.37 why one digit error??
For detail I attach pic of parameters..
1. See the most recommended answer to this question:
https://www.researchgate.net/post/I_want_to_calculate_capacitance_from_CV_data_Can_anybody_please_tell_me_which_value_of_potential_I_have_to_take_for_making_the_calculations
2. You can't verify the calculations in this table because "Area of CV curve" must be measured in volt x ampere, not cm2 (big mistake).
3. Observe also lines 8 and 10 in the same table.
3. In a common CV, on the y axis you have current density: choose the option "electrode area = 1 cm2" to see the current in A, not A/cm2 (a value not altered by division, by electrode area)
Thanks but any formula to convert cm area to amper * volt?
Explain this plz .
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