Hi
I just ordered XRD plate ( Quartz plate).
when I run the plate without sample I got the results on the picture is this results normal ?
and How can I calpreat the plate to get good result?
any suggestion what to do?
thanks alot
I'm not exactly sure what you want to know. That looks like an amorphous signal from the quartz glass. Not too difficult to subtract, especially after measuring it without a sample. If you want to reduce the background from the amorphous scatter you can use a crystalline quartz holder in a non-diffracting orientation. The one thing which is concerning, though, is that at higher angles the scattering seems to actually begin increasing. This could be due to a number of things, depending on the geometry of the scan and the detector. Is it a point detector with a slit or a CCD? If you are using Bragg-Brentano geometry has a correction been made for the change in illuminated volume as a function of theta? The more details you give the more likely that you will get a useful answer.
I'm not exactly sure what you want to know. That looks like an amorphous signal from the quartz glass. Not too difficult to subtract, especially after measuring it without a sample. If you want to reduce the background from the amorphous scatter you can use a crystalline quartz holder in a non-diffracting orientation. The one thing which is concerning, though, is that at higher angles the scattering seems to actually begin increasing. This could be due to a number of things, depending on the geometry of the scan and the detector. Is it a point detector with a slit or a CCD? If you are using Bragg-Brentano geometry has a correction been made for the change in illuminated volume as a function of theta? The more details you give the more likely that you will get a useful answer.
can I use this plate for analysis ?
it will effect my results ?
This is a classical pattern of an amorphous material. You can have problems when you collect a pattern of another amorphous material, that present the same peak of the sample holder, particularly if you want to quantify its amount. In case of crystalline phases you can simply subtract the contribution of sample holder, as suggested by Lawrence.
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