Actually my concern is for the reflection from a Silver/Aluminium mirror, at an angle of incidence of 45 degrees. And the wavelength is in the visible range.
Recall, s-polarized light and p-polarized light reflect differently and depend on incidence angle so you can expect some small deviations in your polarization state. However, by using a silvered mirror in the visible range, you are doing everything you can to minimize this effect.
RCP changes to LCP on reflection at normal incidence whether the reflecting medium is metallic or dielectric. In your case (metallic reflection at an angle of incidence different from zero) the reflected beam will be in general elliptically polarized.
In case anyone finds this thread later and is looking for an easy reference for doing the calculation, here is a link to a free online optics textbook showing the Fresnel equations for reflections from a metal surface.
In normal incidence, whether it is metal or dielectric there is phase difference of pi introduced between p and s components of light. There is also same amplitude (p and s) for both the components upon normal incidence. Hence RCP will become LCP and vice versa. For other angle of incidence, one has to refer to graphs from any standard book for the phase difference and amplitude difference between p and s components and the final state has to be concluded.