A concentration C of ammonium hydroxide ranging from 0.14 to 0.57 M (V = 0.75–3 mL) How to calculate this, NH4OH is 25%and Mw is 35.05, Density 0.91
How to calculate the M ?
- Solution 1 was obtained by rapidly pouring 2.34 mL of TEOS in 20 mL of absolute ethanol and solution 2 by mixing 11.7 mL of deionized water, 17.5 mL of absolute ethanol, and a concentration C of ammonium hydroxide ranging from 0.14 to 0.57 M (V = 0.75–3 mL).
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We can retrieve densities of ammonia (aq. sol.) from (e.g.) Table 2-32, in: R.H. Perry, D.W. Green, J.O. Maloney (Eds.), "Perry's Chemical Engineers’ Handbook", 7th ed., McGraw-Hill, 1997.
For ammonia (aq. sol.) of label concentration 25 wt% as NH3 (approximate) at 20 ºC; ρ = 0.907 g/cm3 (interpolated). The molecular mass of NH3 is 17.03 g/mol. Hence, the molarity in terms of NH3 would be: 0.25(g NH3 / g aq. sol.)·0.907(g aq. sol. / cm3)·(1000 cm3/dm3)/(17.03 g NH3/mol NH3) = 13.3 M as NH3 (approximate).