"Wurtzite is the name given to the mineral ZnS. It has a hexagonal close packed array of S and the Zn(II) sit in tetrahedral (1/2 occupied) sites in the lattice"
As the size of S2- ion is 184pm and Zn+2 is 74pm and therefore the size of tetrahedral void of HCP of S2- is (0.225*R= 41.4pm), how is possible for the Zn2+ to go in the tetrahedral site of S2- hcp?
Please clarify how is it possible in the wurtzite structure?
here the value of R will not be 184 pm it will be the lattice parameter. you can search the ZnS wurtzite structure. the boundary of both ions donot coincide
wurtzite (as ZnS) has unit cell parameters a = 3.82 A and c = 6.26 A (roughly). If you check the ionic size ratio, you are at the upper limit to expect a tetrahedral coordination, but this is what you actually get. Atoms in the cell are at 1/3 2/3 0 and 1/3 2/3 z where z is around 0.384. The distance between the two atoms is therefore larger than the sum of ionic radii
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