For Raman spectra you need to use wavelength which is out of absorption range. In that case your Raman spectra will not be disturbed by fluorescence.

Raman scattering is an inelastic scattering phenomena when the energy of the phonons are measured based on the energy difference between the incident light and scattered photons. The phonon energy measured is independent of the incident laser wavelength, however, the intensity of the Raman line measured can be impacted by effects such as resonance wavelength. The main factor for having Raman active modes depends on whether there is any change in polarizability associated with specific phonon mode. For example, for a mode that does not have change in polarizability, while it has changes in the dipole radiation, the mode will be Raman forbidden but IR active, while for a mode with changes in polarizability but no dipole radiation it will be Raman active and IR forbidden.

Ideally any material that fluoresce would not be expected to be Raman active

Thanks Gagik G. Gurzadyan sir for your reply. i will use try to use higher wavelength laser.

Thanks Bahram Roughani sir for your reply. Actually fluorescence property of molecules sometimes effect raman spectra.

Thanks Adeyinka Aina sir for your reply. We can obtain raman spectra for fluorescent compounds by using laser for higher wavelength. Best suitable laser will be 1024.

Fluorescence is an electronic transition and not directly related to Raman scattering which is vibrational. However, fluorescence is a much stronger signal if you are in the absorption band and exciting fluorescence. Your Raman signal is still there, but just too weak to see. If you can't move to a longer wavelength sometimes photobleaching can make it possible to see the Raman signal.

Nicholas Edward Schlotter Thanks sir for this valuable information.