I am doing my research on metal nanaparticles by using laser ablation in liquid.. I have observed a decrease in particle size with an increase in laser fluence.
1.Pressure of liquid vapor close to its saturated vapor pressure at the melting temperature of the target (hundreds of atmospheres). Reduced droplet sizes.
2. Drops in a confined space may return to the laser beam. Increasing droplet sizes.
3. For a primitive model of the process it can be assumed that the Laplace pressure, stabilizing drop equal to the pressure of saturated liquid vapors.
2. Formula:
2 surface tension of the drop / radius of the drop = vapor pressure.
Calculate the approximate size of the drop (nanoparticles) to your systems.
Regards.
DearTanzeeha Jafari:
During laser ablation, pulsed laser action leads to an explosive release of substances from the target in the form of nanoparticles which were deposited on the substrate. At high energy of the explosion more sprinkling of smaller particles, as in the usual explosion. The liquid medium formed colloids. Due to thermal diffusion, aggregation may occur and phase transitions of the resultant particles. Transformation largely activated depending on the temperature and pressure in the area of impact. The pressure has a significant influence on the formation of particles in a liquid medium. This is due to the fact that the liquid medium forms a significant restriction on the distribution of the plasma cloud, which in turn leads to a higher temperature, density and pressure Also, at the liquid-plasma partition holds heating and evaporation of the liquid, which leads to additional chemical reactions.
Best regards.
1.Pressure of liquid vapor close to its saturated vapor pressure at the melting temperature of the target (hundreds of atmospheres). Reduced droplet sizes.
2. Drops in a confined space may return to the laser beam. Increasing droplet sizes.
3. For a primitive model of the process it can be assumed that the Laplace pressure, stabilizing drop equal to the pressure of saturated liquid vapors.
2. Formula:
2 surface tension of the drop / radius of the drop = vapor pressure.
Calculate the approximate size of the drop (nanoparticles) to your systems.
Regards.
Dear Ashish Sir,
how you dont know this simple process.? anyway come on ww will discuss.
- Badges
- Science topic
- Similar topics
- Chemistry
- Nanotechnology
- Nanostructured Materials
- Nanoparticles