Gravitation
Delta\tau_g = \frac{g}{c^2} \sum_{i=1}^{k} (h_i - h_0) \Delta t_i
How the difference between 0m and 5000m on Earth should be today (after for example 4.5 billion years):
\Delta\tau_g = \frac{~10}{9*10^{16}} (5000m - 0m) 4.5*10^9 years = 21.9 hours
Following the theory, shouldn't we see a difference of 21.9 hours between two picture of the sky taken at 0m and 5000m?
link: http://fr.wikipedia.org/wiki/Utilisateur:N738139
http://www.conspiracyoflight.com/Paradox/The_Paradox_of_the_Clocks_in_the_Canaries.html