I ask myself if the method below could explain relativity, where two different referentials are quantum states shifted by velocity.
1. First (read to the end to understand) I propose you to use theoretical GALILEAN transformations (they should be used without aberration of light) for determining the positions of particles between two referentials A and B. (But here they are only used to help us finding positions of light for each referential since we consider uncertainty between referentials.)
2. Once moved, consider the speed of light to be c. You see that (the INFORMATION/position of) objects of referential A moved with referential B (like everything would be static) for B. The same for referential A, where objects (of B) seems not to have moved. (Actually the motion is calculated as: "V+v-v", galilean speed of light minus/plus motion of the ref.) Adding uncertainty principle, it means you have a QUANTUM STATE for each referential (shifted relative to the other) refering to a same static situation.
3. Finally add light ABERRATION/RETARDATION (the image of objects for each referentials are shifted back to their respective positions).
To conclude you obtain for each observer a relativistic situation where c is constant.
Would it be possible (like we were moving with our sunbeams)?
Dear V. T. Toth,
But LT doesn't work for every situations.
https://www.researchgate.net/post/Is_it_possible_to_have_time_contraction_and_lengths_dilation_in_a_moving_referential_too
And SRT/GR seems to have limits.
https://www.researchgate.net/post/Is_relative_simultaneity_a_misinterpretation_of_Special_Relativity
I don't wanted to be rude for downvoting your answer, but what I ask is if this alternative conception could be true, not to affirm there is only one way to think.
(For remark, if you reconsider my question here invariance is not broken.)
Dear Ni Ge,
Now everything is solved. There is no graviton, it is photon. There is no space-time continuum or curved spacetime. It is only time and space is invariant. The decrease in the space of the light globaly is depending on the gravitation potential potential where c'=(1-GM/c^2r)c. The gravitational time dilation is t'=(1-GM/c^2r)t. Now what about the factor of 2 in the Schwarzschild geometry which causing the solve the precession, light bending of gravity and Shapiro delay. According to my transforms the Lorentz factor is is equivalent to the refractive index in optics. Review my paper again http://dx.doi.org/10.14299/ijser.2014.10.002 and my transforms are leading to wave-particle duality and Heisenberg uncertainty principle and the vacuum energy depending.
Starting from the dispersion ω(k), we define the phase velocity as
vp =ω/k
and the group velocity as
vg =∂ω/∂k
Obviously, these two are the same for a linear dispersion with ω(k) = ak.
For a free, non-relativistic quantum mechanical particle of mass m, we have
E(k) = h(bar)ω(k) = h(bar)2k2/2m
In case of free falling object under gravity in weak gravitational field, globally the dispersion is not linear, So even if we start with a fairly localized “particle”, it will soon loose this localization. We can calculate the group velocity for this dispersion as
vg =∂ω(k)/∂k =h(bar)k/m
and this is perfectly consistent with the movement of a semiclassical particle for
which the momentum is p = h(bar)k and the group velocity thus p/m = vg.
Now the factor of 2 which exists in Shwarzschild solution is solved according to quantum. In fact the Lorentz factor according to my transforms is equivalent to the refractive index in optics. The classical momentum of the particle equivalent to the escape velocity of the free fall object under gravitational field is related globally to the group velocity of a wave packet, which turns out to be p/m. Now Shapiro delay, the Pioneer anomaly and the energy momentum problem, precession, light bending by gravity are all solved completely by group velocity and the wave-particle duality. In fact thanks to quantum theory, it has all the interpretations!
Dear Ni Ge,
Now everything becomes clear, in case of Pound and Rebka experiment, the measurement was happening in two fixed points at constant radius from the center of mass in gravitation field, and there is no change on the radius. In this case each point is considered as an inertial frame of reference, because there is no change in the radius from the centre of mass. These two point are localized and fixed. In this case the group velocity and the phase velocity are equal, and time dilation are given according to t=t'(1-GM/c^2r) which is depending on the gravitational potential according to my equivalence principle.
For a free, non-relativistic quantum mechanical particle of mass m, we have
E(k) = h(bar)ω(k) = h(bar)2k2/2m
Now for Light bending by gravity and the precession, the dispersion is not linear because of motion under gravitational and changing the radius from the center of mass during the motion. So even if we start with a fairly localized “particle”, it will soon loose this localization. In this case the group velocity is not equal to the phase velocity.
We can calculate the group velocity for this dispersion as
vg =∂ω(k)/∂k =h(bar)k/m
and this is perfectly consistent with the movement of a semiclassical particle for
which the momentum is p = h(bar)k and the group velocity thus p/m = vg. In this case the classical velocity is not the phase velocity, it is the group velocity which accounts now exactly the precession, the light bending by gravity, Shapiro delay, the Pioneer anomaly. Now everything becomes clear and very simple.
It was really very complicated and confusing problemmmmm!!!!
Dear Akira,
You try to interpret that according to Einstein relativity theory. Now the problem solved in different way from Einstein. Read my paper and read my transformations and my equivalence, everything is now quantum and the wave-particle duality. Forget now Einstein equivalence principle. This my paper http://dx.doi.org/10.14299/ijser.2014.10.002
- Badges
- Science topic
- Similar topics
- Physical Sciences
- Quantum Physics
- Quantum Mechanics