If we use the equimolar quantity of the alkyl halide and 4-(Dimethylamino)pyridine then which of the two Nitrogen atoms of 4-(Dimethylamino)pyridine will be alkylated? is there any theoretical evidence for the same?
Out of the two Nitrogen atoms of the 4-(Dimethylamino)pyridine , the pyridyl nitrogen is susceptible for alkylation as it is less sterically hindered than 4-Dimethylamino in pyridine.
Both N atoms are sp2 hybridized. Although the exocyclic N seems to be more basic (but is not) is less nucleophylic. Then alkylation occurs on the ring N atom (by kinetic control), as would also protonation occur (by thermodynamic control).