what the difference between the interaction of electromagnetic radiation with metals and semiconductor?
Dear Mokhalad,
welcome,
Any material reacts on the incident electromagnetic radiation by reflecting a part, absorbing a part and transmitting the rest.
Metals reflects the incident electromagnetic radiation, the penetrating depth which is called skin depth depends on the frequency of the incident waves.
It decreases with the frequency increase.
In case of semicondcutors, a part will be reflected at the surface and the waves which have a wave length greater than the critical wavelength will be pass unattenuated in the material. The radiation with shorter wavelength will be absorbed by the material if its thickness is greater than the inverse of the absorption coefficient. So, one can say it will be attenuated.
The reflection occurs because mismatch in the wave impedance of the two medium at the interface.
Best wishes
The practical frequency range of electromagnetic radiation is enormous, so one has to be more specific. Generally, one typically should expect few orders of magnitude less carrier concentration in semiconductors. That makes for a very different value of "Critical_frequency":
https://en.wikipedia.org/wiki/Critical_frequency
However, it is much more complicated than just that. An interesting review is e.g. here: https://www.curtwittig.com/wp-content/uploads/IV.-pp.215-322.pdf
Dear Mokhalad,
welcome,
Any material reacts on the incident electromagnetic radiation by reflecting a part, absorbing a part and transmitting the rest.
Metals reflects the incident electromagnetic radiation, the penetrating depth which is called skin depth depends on the frequency of the incident waves.
It decreases with the frequency increase.
In case of semicondcutors, a part will be reflected at the surface and the waves which have a wave length greater than the critical wavelength will be pass unattenuated in the material. The radiation with shorter wavelength will be absorbed by the material if its thickness is greater than the inverse of the absorption coefficient. So, one can say it will be attenuated.
The reflection occurs because mismatch in the wave impedance of the two medium at the interface.
Best wishes
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