In the capacitive (non-Faradaic) region of CV, there is no transfer of ions or electrons across the electrode (from one bulk phase to another bulk phase). You can calculate the charging currents from CVs in the double layer region at different scan rates. A plot of charging current vs scan rate (dE/dt) will give you a straight line graph from which you can calculate the slope (I/dE/dt). The slope will give you double-layer capacitance because of C=Q/V=It/V = I/V/t. You can use this information to calculate the roughness factor (experimental double-layer capacitance/ double-layer capacitance at an ideally smooth surface).

According to Mohilner et al., at an ideal polarized electrode, faradaic processes are prohibited. Whenever a real electrode behaves as an ideal polarized electrode, it is because, within a certain range of potentials, all the faradaic processes which might conceivably take place there fall into either of two categories; (a) The activation energy is so high that the faradaic process occurs at a negligible rate. [...] (b) Even though the activation energy is low, the equilibrium constant for the faradaic process is such that the concentration of either reactants or products is so low as to be meaningless (except in a statistical sense). Therefore, any charge transfer accompanying a change of electrode potential is entirely negligible. You can use this information to make useful conclusions.

Example: The processes of adsorption and desorption which take place whenever the structure of the electrical double layer changes are nonfaradaic. At ideal polarized electrodes, only nonfaradaic processes can take place, but at charge-transfer electrodes, both faradaic and nonfaradaic processes occur simultaneously.

Dear Asis Sethi

Please try to see this book

Manipulation d'électrochimie - J.Besson and J.Quitton 1972.

simply the capacitive current is the non-faradic range og CV, therefore the ions and electrons transfer are null